jquery – 推荐的方式来处理Thymeleaf Spring MVC AJAX Forms及其错误消息

这是写在Spring 4.2.1和Thymeleaf 2.1.4中

表示用户信息表单的基本类：UserInfo.java

package myapp.forms;

import org.hibernate.validator.constraints.Email;
import javax.validation.constraints.Size;
import lombok.Data;

@Data
public class UserInfo {
  @Email
  private String email;
  @Size(min = 1,message = "First name cannot be blank")
  private String firstName;
}

控制器：UsersAjaxController.java

import myapp.forms.UserInfo;
import myapp.services.UserServices;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.*;

import javax.transaction.Transactional;

@Controller
@Transactional
@RequestMapping("/async/users")
public class UsersAjaxController {
  @Autowired
  private UserServices userServices;

  @RequestMapping(value = "/saveUserInfo",method = RequestMethod.POST)
  public String saveUserInfo(@Valid @modelattribute("userInfo") UserInfo userInfo,BindingResult result,Model model)  {
    // if any errors,re-render the user info edit form
    if (result.hasErrors()) {
        return "fragments/user :: info-form";
    }
    // let the service layer handle the saving of the validated form fields
    userServices.saveUserInfo(userInfo);
    return "fragments/user :: info-success";
  }
}

用于呈现表单和成功消息的文件：fragments / user.html

<div th:fragment="info-form" xmlns:th="http://www.thymeleaf.org" th:remove="tag">
  <form id="userInfo" name="userInfo" th:action="@{/async/users/saveUserInfo}" th:object="${userInfo}" method="post">
    <div th:classappend="${#fields.hasErrors('firstName')}?has-error">
      <label class="control-label">First Name</label>
      <input th:field="*{firstName}" type="text" />
    </div>
    <div th:classappend="${#fields.hasErrors('first')}?has-error">
      <label class="control-label">Email</label>
      <input th:field="*{email}" ftype="text" />
    </div>
    <input type="submit" value="Save" />
  </form>
</div>

<div th:fragment="info-success" xmlns:th="http://www.thymeleaf.org" th:remove="tag">
  <p>Form successfully submitted</p>
</div>

JS代码将简单地将表单提交到表单action属性中提供的URL.当响应返回到JS回调时,检查是否有任何错误.如果有错误,请将表单替换为响应中的表单.

(function($){
  var $form = $('#userInfo');
  $form.on('submit',function(e) {
    e.preventDefault();
    $.ajax({
      url: $form.attr('action'),type: 'post',data: $form.serialize(),success: function(response) {
        // if the response contains any errors,replace the form
        if ($(response).find('.has-error').length) {
          $form.replaceWith(response);
        } else {
          // in this case we can actually replace the form
          // with the response as well,unless we want to 
          // show the success message a different way
        }
      }
  });
}(jQuery));

再次,这只是一个基本的例子.如上述评论中所提到的,没有正确的或错误的方法来解决这个问题.这不是我的首选解决方案,绝对有一些调整,我会做,但一般的想法是在那里.

注意：我的JS代码中还有一个缺陷.如果将表单与响应中的表单替换,则表单提交处理程序将不会应用于新替换的表单.如果进入此路由,则需要确保在更换表单后正确重新初始化表单处理程序.