我已经编写代码来尝试捕获StackOverFlowExceptions：
try { recursiveFxn(100000); }
catch(Exception){}
private void recursiveFxn(int countdown)
{
if (countdown > 0)
recursiveFxn(countdown - 1);
else
throw new Exception("lol. Forced exception.");
}
但是我仍然遇到程序崩溃(在NUnit和我正在运行的网页).为什么没有捕获异常？
解决方法
Starting with the .NET Framework
version 2.0,aStackOverflowException
object cannot be caught by a try-catch
block and the corresponding process is
terminated by default. Consequently,
users are advised to write their code
to detect and prevent a stack
overflow. For example,if your
application depends on recursion,use
a counter or a state condition to
terminate the recursive loop.
现在,捕获StackOverflowException的唯一方法是当用户代码抛出时,如blog by Jared Parsons所述.除了hosting the CLR之外,您可以处理(但不是捕获)StackOverflowException,并设计出一种方法来执行你的程序继续
请注意,由于堆栈在发生异常时展开,在2.0版本的.Net中,当处理StackOverflowException时,堆栈实际上会更短,这样可以在不生成另一个StackOverflowException的情况下执行此操作.