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How to force JS to do math instead of putting two strings together7个答案我想添加所有的卡路里内容在我的javascript像这样：
$(function() {
var data = [];
$( "#draggable1" ).draggable();
$( "#draggable2" ).draggable();
$( "#draggable3" ).draggable();
$("#droppable_Box").droppable({
drop: function(event,ui) {
var currentId = $(ui.draggable).attr('id');
var total = 0;
data.push($(ui.draggable).attr('id'));
if(currentId == "draggable1"){
var myInt1 = parseFloat($('#MealplanCalsPerServing1').val());
}
if(currentId == "draggable2"){
var myInt2 = parseFloat($('#MealplanCalsPerServing2').val());
}
if(currentId == "draggable3"){
var myInt3 = parseFloat($('#MealplanCalsPerServing3').val());
}
if ( typeof myInt1 === 'undefined' || !myInt1 ) {
myInt1 = parseInt(0);
}
if ( typeof myInt2 === 'undefined' || !myInt2){
myInt2 = parseInt(0);
}
if ( typeof myInt3 === 'undefined' || !myInt3){
myInt3 = parseInt(0);
}
total = parseFloat(myInt1 + myInt2 + myInt3);
$('#response').append(total);
}
});
$('#myId').click(function(event) {
$.post("process.PHP",({ id: data }),function(return_data,status) {
alert(data);
//alert(total);
});
});
});
而不是添加变量，它们被连接起来。我试过使用parseInt，parseFloat和Number，但我仍然只是连接而不是添加。请在http://maureenmoore.com/momp_112412/121912_800.html查看来源
解决方法
您的代码连接三个字符串，然后将结果转换为一个数字。
您需要通过每个变量调用parseFloat()将每个变量转换为一个数字。
total = parseFloat(myInt1) + parseFloat(myInt2) + parseFloat(myInt3);