我在
android上开发应用程序！
好吧,我现在有一点冲突,我想执行一个XPath查询,但我没有到达解决这个问题.
这是我使用的XML文件的一个例子：
<?xml version="1.0"?> <catalog> <book id="bk101"> <author>Gambardella,Matthew</author> <title>XML Developer's Guide</title> <genre>Computer</genre> <price>44.95</price> <publish_date>2000-10-01</publish_date> <description>An in-depth look at creating applications with XML.</description> </book> <book id="bk102"> <author>Ralls,Kim</author> <title>Midnight Rain</title> <genre>Fantasy</genre> <price>5.95</price> <publish_date>2000-12-16</publish_date> <description>A former architect battles corporate zombies,an evil sorceress.</description> </book> <book id="bk103"> <author>Corets,Eva</author> <title>Maeve Ascendant</title> <genre>Fantasy</genre> <price>5.95</price> <publish_date>2000-11-17</publish_date> <description>After the collapse of a nanotechnology society in England.</description> </book> </catalog>
我能怎么做？？
提前致谢！！
解决方法
看看这个例子：
import java.io.FileReader;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class GuestList {
public static void main(String[] args) throws Exception {
XPathFactory factory = XPathFactory.newInstance();
XPath xPath = factory.newXPath();
NodeList shows = (NodeList) xPath.evaluate("/schedule/show",new InputSource(new FileReader(
"tds.xml")),XPathConstants.NODESET);
for (int i = 0; i < shows.getLength(); i++) {
Element show = (Element) shows.item(i);
String guestName = xPath.evaluate("guest/name",show);
String guestCredit = xPath.evaluate("guest/credit",show);
System.out.println(show.getAttribute("weekday") + "," + show.getAttribute("date") + " - "
+ guestName + " (" + guestCredit + ")");
}
}
}
其余的例子在这里：http://jexp.ru/index.php/Java_Tutorial/XML/XPath