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Finding index of character in Swift String2
我想将字符串中包含的字母的索引转换为整数值。尝试读取头文件，但是我找不到Index的类型，尽管它似乎符合使用方法(例如distanceto)的ForwardindexType协议。
我想将字符串中包含的字母的索引转换为整数值。尝试读取头文件，但是我找不到Index的类型，尽管它似乎符合使用方法(例如distanceto)的ForwardindexType协议。
var letters = "abcdefg"
let index = letters.characters.indexOf("c")!
// ERROR: Cannot invoke initializer for type 'Int' with an argument list of type '(String.CharacterView.Index)'
let intValue = Int(index) // I want the integer value of the index (e.g. 2)
任何帮助是赞赏。
您需要使用与原始字符串起始索引相关的distanceto(index)方法：
let intValue = letters.startIndex.distanceto(index)
您还可以使用一种方法扩展字符串，以返回字符串中第一个出现的字符串，如下所示：
extension String {
func indexdistanceOfFirst(character character: Character) -> Int? {
guard let index = characters.indexOf(character) else { return nil }
return startIndex.distanceto(index)
}
}
let letters = "abcdefg"
let char: Character = "c"
if let index = letters.indexdistanceOfFirst(character: char) {
print("character \(char) was found at position #\(index)") // "character c was found at position #2\n"
} else {
print("character \(char) was not found")
}
Xcode 8 beta 3•Swift 3
extension String {
func indexdistance(of character: Character) -> Int? {
guard let index = characters.index(of: character) else { return nil }
return distance(from: startIndex,to: index)
}
}
let letters = "abcdefg"
let char: Character = "c"
if let index = letters.indexdistance(of: char) {
print("character \(char) was found at position #\(index)") // "character c was found at position #2\n"
} else {
print("character \(char) was not found")
}