我有一个像这样的长字符串：
je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?
我想在之后拆分字符串：之前？ .所以我想进入数组：
{e,es,e,ons,ez,en}
我知道我可以这样做：
NSArray *subStrings = [stringtochange componentsSeparatedByString:@":"];
但这还不够.
我该怎么办？任何帮助将不胜感激！
解决方法
另一种选择可能是使用
NSRegularExpression类.
使用这种模式：
\\:([^\?]+)\?
示例代码：
Nsstring *sample = @"je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?";
Nsstring *pattern = @"\\:([^\?]+)\?";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive
error:&error];
NSArray *matches = [regex matchesInString:sample
options:0
range:NSMakeRange(0,[sample length])];
if(!error && [matches count] > 0) {
for (NSTextCheckingResult *match in matches) {
NSRange matchRange = [match range];
NSLog(@"%@",[sample substringWithRange:matchRange]);
}
}
输出：
2015-07-03 12:16:39.037 TestRegex[3479:48301] :e 2015-07-03 12:16:39.039 TestRegex[3479:48301] :es 2015-07-03 12:16:39.039 TestRegex[3479:48301] :e 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ons 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ez 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ent