我正在做这样的动画：
CAKeyframeAnimation *animation = [CAKeyframeAnimation animationWithKeyPath:@"position"];
animation.duration = 100.0;
animation.path = self.animationPath.CGPath;
[view.layer addAnimation:animation forKey:@"animation"];
工作正常,但是,当尝试检测在屏幕上移动的对象上的触摸时,现在会失败：
- (BOOL)pointInside:(CGPoint)point withEvent:(UIEvent *)event
{
for (UIView* subview in self.subviews ) {
if ( [subview hitTest:[self convertPoint:point toView:subview] withEvent:event] != nil ) {
[self handleTap];
return YES;
}
}
return NO;
}
它失败了,因为视图的帧不再与它在动画时在屏幕上的明显位置相同.如何让pointInside与正在设置动画的视图一起使用？
解决方法
这是我执行此操作的代码
#import "ViewController.h"
@interface ViewController ()
@property (weak,nonatomic) IBOutlet AnimatableView *animableView;
@end
@implementation ViewController
- (void)animatealongPath
{
UIBezierPath * path = [UIBezierPath bezierPathWithRect:self.view.frame];
CAKeyframeAnimation *animation = [CAKeyframeAnimation animationWithKeyPath:@"position"];
animation.duration = 10;
animation.path = path.CGPath;
animation.removedOnCompletion = NO;
animation.fillMode = @"kCAFillModeForwards";
[self.animableView.layer addAnimation:animation forKey:@"animation"];
}
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view,typically from a nib.
}
- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// dispose of any resources that can be recreated.
}
- (IBAction)animate:(id)sender {
[self animatealongPath];
}
-(void)touchesBegan:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event
{
UITouch *touch = [touches anyObject];
CGPoint location = [touch locationInView: [touch view]];
CALayer * selectedlayer = (CALayer*)[self.animableView.layer.presentationLayer hitTest:location];
if(selectedlayer != nil)
NSLog(@"touched");
else
NSLog(@"dont touched");
}
@end
我希望这可以帮助你