g – Mixins,可变模板和C中的CRTP

这是这个场景：我想要一个主机类,它可以有一个可变数量的混合(不是太多的可变模板 – 参见例如 http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.103.144).但是,我也希望由主机类参数化mixins,以便它们可以引用它的公共类型(使用CRTP成语).
当尝试混合这两个问题时出现问题 – 正确的语法对我来说不清楚.
例如,以下代码无法使用g 4.4.1进行编译：

template <template<class> class... Mixins>
class Host : public Mixins<Host<Mixins>>... {
  public:
    template <class... Args>
    Host(Args&&... args) : Mixins<Host>(std::forward<Args>(args))... {}
};

template <class Host> struct Mix1 {};

template <class Host> struct Mix2 {};

typedef Host<Mix1,Mix2> TopHost;
TopHost *th = new TopHost(Mix1<TopHost>(),Mix2<TopHost>());

有错误：

tst.cpp: In constructor ‘Host<Mixins>::Host(Args&& ...) [with Args = Mix1<Host<Mix1,Mix2> >,Mix2<Host<Mix1,Mixins = Mix1,Mix2]’:

tst.cpp:33:   instantiated from here

tst.cpp:18: error: type ‘Mix1<Host<Mix1,Mix2> >’ is not a direct base of ‘Host<Mix1,Mix2>’

tst.cpp:18: error: type ‘Mix2<Host<Mix1,Mix2>’

有没有人有成功的经验混合可变模板与CRTP？

#include <utility>

template <template<class> class... Mixins>
class Host : public Mixins<Host<Mixins...>>...
{
  public:
    Host(Mixins<Host>&&... args) : Mixins<Host>(std::forward<Mixins<Host>>(args))... {}
};

template <class Host> struct Mix1 {};
template <class Host> struct Mix2 {};

int main (void)
{
  typedef Host<Mix1,Mix2> TopHost;
  delete new TopHost(Mix1<TopHost>(),Mix2<TopHost>());
}