参见英文答案 >
Scanf skips every other while loop in C10个
#include "stdio.h"
int main(void)
{
int order,nextp,N=3;
char cont;
nextp = 0;
printf("\nShould we continue (y or n): ");
scanf("%c",&cont);
if (cont != 'y') return;
for(; nextp < N; nextp++)
{
printf("Enter order number: ");
scanf("%d",&order);
printf("you have entered %d\n",order);
printf("okay Now continue with cont\n");
printf("enter cont y or n: ");
scanf("%c",&cont);
if (cont != 'y')
{
printf("\nnot equal to y\n");
break;
}
printf("after intepreting t[0]");
}
return 0;
}
输出看起来像这样
Should we continue (y or n): y Enter order number: 45 you have entered 45 okay Now continue with cont enter cont y or n: not equal to y
第二个输入被跳过了.为什么？
解决方法
由于stdin中已经存在换行符,这种情况正在发生.
使用
使用
scanf(" %c",&cont);
代替
scanf("%c",&cont);
注意％c之前的一个空格.