我试图实现一个解决方案来计算RGB和CMYK之间的转换,反之亦然.这是我到目前为止
public static int[] rgbToCmyk(int red,int green,int blue)
{
int black = Math.min(Math.min(255 - red,255 - green),255 - blue);
if (black!=255) {
int cyan = (255-red-black)/(255-black);
int magenta = (255-green-black)/(255-black);
int yellow = (255-blue-black)/(255-black);
return new int[] {cyan,magenta,yellow,black};
} else {
int cyan = 255 - red;
int magenta = 255 - green;
int yellow = 255 - blue;
return new int[] {cyan,black};
}
}
public static int[] cmykToRgb(int cyan,int magenta,int yellow,int black)
{
if (black!=255) {
int R = ((255-cyan) * (255-black)) / 255;
int G = ((255-magenta) * (255-black)) / 255;
int B = ((255-yellow) * (255-black)) / 255;
return new int[] {R,G,B};
} else {
int R = 255 - cyan;
int G = 255 - magenta;
int B = 255 - yellow;
return new int[] {R,B};
}
}
解决方法
正如Lea Verou所说,您应该使用颜色空间信息,因为没有从RGB映射到CMYK的算法. Adobe有一些ICC颜色配置文件可供下载
1,但我不知道他们是如何获得许可的.
一旦你有颜色配置文件,如下面的工作：
import java.awt.color.ColorSpace;
import java.awt.color.ICC_ColorSpace;
import java.awt.color.ICC_Profile;
import java.io.IOException;
import java.util.Arrays;
public class ColorConv {
final static String pathToCMYKProfile = "C:\\UncoatedFOGRA29.icc";
public static float[] rgbToCmyk(float... rgb) throws IOException {
if (rgb.length != 3) {
throw new IllegalArgumentException();
}
ColorSpace instance = new ICC_ColorSpace(ICC_Profile.getInstance(pathToCMYKProfile));
float[] fromrGB = instance.fromrGB(rgb);
return fromrGB;
}
public static float[] cmykToRgb(float... cmyk) throws IOException {
if (cmyk.length != 4) {
throw new IllegalArgumentException();
}
ColorSpace instance = new ICC_ColorSpace(ICC_Profile.getInstance(pathToCMYKProfile));
float[] fromrGB = instance.toRGB(cmyk);
return fromrGB;
}
public static void main(String... args) {
try {
float[] rgbToCmyk = rgbToCmyk(1.0f,1.0f,1.0f);
System.out.println(Arrays.toString(rgbToCmyk));
System.out.println(Arrays.toString(cmykToRgb(rgbToCmyk[0],rgbToCmyk[1],rgbToCmyk[2],rgbToCmyk[3])));
} catch (IOException e) {
e.printstacktrace();
}
}
}