"Parameters": {
"ELBsubnets": {
"Default": "subnet-5d8fea67,subnet-3e35cf15","Type": "CommaDelimitedList"
},"LCKeyPair": {
"Default": "key-master","Type": "String"
},"LCSecurityGroups": {
"Default": "sg-10a15c74,sg-880e5fec","Type": "CommaDelimitedList"
}
},
传递给子模板时,它们在同一模板上的此方法中被引用.
"ChildTempate1": {
"Properties": {
"Parameters": {
"ELBsubnets": {
"Ref": "ELBsubnets"
},"KeyPair": {
"Ref": "LCKeyPair"
},"LCSecurityGroups": {
"Ref": "LCSecurityGroups"
}
},
在子模板上,它们被声明完全相同.
"Parameters": {
"ELBsubnets": {
"Type": "CommaDelimitedList"
},"LCKeyPair": {
"Type": "String"
},"LCSecurityGroups": {
"Type": "CommaDelimitedList"
}
},
并且它们在子模板中的此方法中被引用.
"KeyName": {
"Ref": "LCKeyPair"
},"SecurityGroups": {
"Fn::Join": [
",",[
{
"Ref": "LCSecurityGroups"
}
]
]
}
},
这是模板的另一部分.
"subnets": {
"Fn::Join": [
",[
{
"Ref": "ELBsubnets"
}
]
]
}
},
当我尝试在主模板上使用fn :: join时,它说
“Template validation error: Template error: every Fn::Join object requires two parameters,(1) a string delimiter and (2) a list of strings to be joined or a function that returns a list of strings (such as Fn::GetAZs) to be joined.”
当我不在主模板上使用fn :: join时,错误是
Value of property Parameters must be an object with String (or simple type) properties
无论我是否在子模板中使用fn :: join相同的参数.
这两个模板都可以在这里找到：https://github.com/slimg00dy/Troposphere-CloudformationTests
解决方法
因此,在主模板上,我使用Join(“,”)传递列表,使用Join(“”)传递字符串.这样它们被称为“a,c”和“String”
在子模板上,我将参数设置为列表的CommaDelimitedLists和String中的String.这是因为它们从主模板传递的方式.
然后我在子模板上使用Ref on the Child模板而不使用Join().这将CommaDelimitedLists创建为Lists,并将以Join(“”)连接的字符串作为字符串传递.
这是我在主模板上的参数声明.
"Parameters": {
"ELBsubnets": {
"Default": "subnet-5d8fea67,
这是我如何使用Join(“,”),Join(“”)和Ref.由于Ref将CommaDelimitedLists转换为Lists,因此我使用Join(“,”)将它们保存为CommaDelimitedLists并将它们传递给子模板.
至于KeyPair字符串,我确保它在父模板上被声明为CommaDelimitedList并与Join(“”)连接,这在引用子模板时有效地使其成为字符串.
"Parameters": {
"ELBsubnets": {
"Fn::Join": [
",{
"Ref": "ELBsubnets"
}
]
},"LCKeyPair": {
"Fn::Join": [
" ",{
"Ref": "LCKeyPair"
}
]
},"LCSecurityGroups": {
"Fn::Join": [
",{
"Ref": "LCSecurityGroups"
}
]
}
},它们被声明为这样.
"Parameters": {
"ELBsubnets": {
"Type": "CommaDelimitedList"
},
并且它们都是正常引用而不使用子模板上的Join.
subnets": {
"Ref": "ELBsubnets"
}
可能有很多不同的方法可以做到这一点.我可以在子模板而不是父模板上进行连接.但是,我更喜欢保持一个模板复杂,其余模板尽可能干净.希望这有助于其他人.
我也应该能够将列表作为列表传递给子模板,然后我收到错误“UnkNown parameter type：List”