c# – 如何将GridView作为ConverterParameter传递

以下是XAML列表视图和Converter类的一部分.

任何帮助非常感谢.谢谢！！！

<ListView Name="SeqDtStDataListView1" Grid.Row="1" 
        DataContext="{Binding Path=displayDT[0],Converter ={StaticResource      
                                                       CNVToColumn},ConverterParameter=?????}"
        VerticalContentAlignment="Stretch" VerticalAlignment="Stretch"
                                                       HorizontalAlignment="Stretch"
        SelectionChanged="SEQDatalistview_SelectionChanged"  Margin="5"> 


       <ListView.View >
             <GridView x:Name="SeqDtStDataGridView1"/>
       </ListView.View>
    </ListView>

转换器：

namespace MFTest.Converters
{
public class CNVToColumn : IValueConverter
{

    public object Convert(object value,Type targettype,object parameter,System.Globalization.CultureInfo culture)
    {
        DataTable dt = (DataTable)value;
        GridView GV = (GridView)parameter;                <========= fail here ===========
        if (dt != null && GV != null)
          foreach (var colum in dt.Columns)               // Binding the Columns
          {
                DataColumn dc = (DataColumn)colum;
                GridViewColumn column = new GridViewColumn();
                column.displayMemberBinding = new Binding(dc.ColumnName);
                column.Header = dc.ColumnName;
                GV.Columns.Add(column);
          } 
        return null;
    }

    public object ConvertBack(object value,System.Globalization.CultureInfo culture)
    {
        throw new NotImplementedException();
    }

}
}