我有一个
Spring控制器正在从
JQuery.post()调用.当它被调用时,控制器的方法被调用并返回.但是,在后台,Spring更改URL并调用服务器的增益.服务器响应404.
我认为这是响应Spring尝试在POST方法被处理后找到一个View.
如何阻止Spring控制器这样做?
这是我的Spring Controller:
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.modelattribute;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import java.util.ArrayList;
import java.util.List;
@Controller
@RequestMapping("/person")
public class DataController {
private List<Person> people = new ArrayList<Person>();
@RequestMapping(value="put",method = RequestMethod.POST)
public void addPerson(@modelattribute("person") Person person){
System.out.println(">>>>>>> person: " + person);
System.out.println(">>>>>>>>> " + person.getFirstName());
people.add(person);
}
}
这是我的应用程序上下文xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="uk.co.jeeni" />
<mvc:annotation-driven />
</beans>
这是我的web.xml文件:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">
<servlet>
<servlet-name>dispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.dispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:applicationContext-web.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcherServlet</servlet-name>
<url-pattern>/data/*</url-pattern>
</servlet-mapping>
</web-app>
这是我的HTML文件中的JQuery调用:
function attachSendDataEvent(){
$("#sendData").click(function(){
var data = "firstName=" + $("#firstName").val() + "&" +
"lastName=" + $("#lastName").val() + "&" +
"address=" + $("#address").val() + "&" +
"postcode=" + $("#postcode").val();
$.post("data/person/put",data,dataSentOK
);
});
return false;
}
dataSentOK函数只执行一个警报(“DONE”).
所以当JQuery方法调用的URL是:
http://localhost:8080/jquery/data/person/put
而在服务器端,System.out.println(…)方法打印出预期的数据.
但是在Firebug中,服务器发回404.
所以我开始使用Spring进行日志记录,得到:
[01] dispatcherServlet [DEBUG] dispatcherServlet with name 'dispatcherServlet' processing POST request for [/jquery/data/person/put] [02] AbstractHandlerMethodMapping [DEBUG] Looking up handler method for path /person/put [03] AbstractHandlerMethodMapping [DEBUG] Returning handler method [public void uk.co.jeeni.DataController.addPerson(uk.co.jeeni.Person)] [04] Abstractbeanfactory [DEBUG] Returning cached instance of singleton bean 'dataController' [05] dispatcherServlet [DEBUG] Rendering view [org.springframework.web.servlet.view.InternalResourceView: name 'person/put'; URL [person/put]] in dispatcherServlet with name 'dispatcherServlet' [06] AbstractView [DEBUG] Added model object 'org.springframework.validation.BindingResult.person' of type [org.springframework.validation.BeanPropertyBindingResult] to request in view with name 'person/put' [07] AbstractView [DEBUG] Added model object 'person' of type [uk.co.jeeni.Person] to request in view with name 'person/put' [08] InternalResourceView [DEBUG] Forwarding to resource [person/put] in InternalResourceView 'person/put' [09] dispatcherServlet [DEBUG] dispatcherServlet with name 'dispatcherServlet' processing POST request for [/jquery/data/person/person/put] [10] AbstractHandlerMethodMapping [DEBUG] Looking up handler method for path /person/person/put [11] AbstractHandlerMethodMapping [DEBUG] Did not find handler method for [/person/person/put] [12] dispatcherServlet [ WARN] No mapping found for HTTP request with URI [/jquery/data/person/person/put] in dispatcherServlet with name 'dispatcherServlet' [13] FrameworkServlet [DEBUG] Successfully completed request [14] FrameworkServlet [DEBUG] Successfully completed request
响应URL POST请求(/ jquery / data / person / put),找到并调用正确的方法(第1行到第7行),但是Spring将转发到第8行的InternalResourceView,该URL将URL更改为/ jquery / data / person / person / put,这是无法找到的.
如何阻止Spring试图找到一个视图.所有我想要做的都是干净地返回并完成.
谢谢你的帮助.
解决方法
解决了.
问题是#CodeChimp建议,除了我仍然想要一个void返回类型.
我添加了@ResponseBody到addPerson方法,一切正常:
@RequestMapping(value="put",method = RequestMethod.POST)
**@ResponseBody**
public void addPerson(@modelattribute("person") Person person){
System.out.println(">>>>>>> person: " + person);
System.out.println(">>>>>>>>> " + person.getFirstName());
people.add(person);
}
线索来自http://static.springsource.org/spring/docs/3.2.x/spring-framework-reference/html/mvc.html#mvc-ann-responsebody.虽然文档不清楚,空白返回会发生什么.只是试过它,它的工作.