在Python中存储三角形/六边形网格的最佳方法

我正在用六角形瓷砖制作游戏,并决定使用三角形/六边形网格.我发现 this问题帮助我生成坐标,并稍微修改了代码,将所有坐标存储为字典中的键,其值为“.”. (floor)或“X”(wall,)并包括一个打印出地图的字符串表示的函数,其中每个非空白字符代表一个六边形图块.这是新代码：

deltas = [[1,-1],[0,1,[-1,0],1],-1,[1,0]]
class HexGrid():
    def __init__(self,radius):
        self.radius = radius
        self.tiles = {(0,0): "X"}
        for r in range(radius):
            a = 0
            b = -r
            c = +r
            for j in range(6):
                num_of_hexas_in_edge = r
                for i in range(num_of_hexas_in_edge):
                    a = a+deltas[j][0]
                    b = b+deltas[j][1]
                    c = c+deltas[j][2]           
                    self.tiles[a,b,c] = "X"

    def show(self):
        l = []
        for y in range(20):
            l.append([])
            for x in range(60):
                l[y].append(".")
        for (a,c),tile in self.tiles.iteritems():
            l[self.radius-1-b][a-c+(2*(self.radius-1))] = self.tiles[a,c]
        mapString = ""
        for y in range(len(l)):
            for x in range(len(l[y])):
                mapString += l[y][x]
            mapString += "\n"
        print(mapString)

使用此代码,我可以生成半径内的所有坐标,如下所示：

import hexgrid
hg = hexgrid.HexGrid(radius)

并访问这样的坐标：

hg.tiles[a,c]

这似乎现在工作正常,但我确信以这种方式存储地图肯定存在一些缺点.如果有任何缺点,请指出它们,并提出更好的存储方式？非常感谢你的时间.

+--+--+--+--+--+--+--+
 \/ \/ \/ \/ \/ \/ \/    Even row

  /\ /\ /\ /\ /\ /\ /\   Odd row
 +--+--+--+--+--+--+--+

__    __    __    __
 /  \__/  \__/  \__/  \__ Even row
 \__/  \__/ A\__/  \__/   Odd  row
 /  \__/ F\__/ B\__/  \__ Even row
 \__/  \__/ X\__/  \__/   Odd  row
 /  \__/ E\__/ C\__/  \__ Even row
 \__/  \__/ D\__/  \__/   Odd  row
 /  \__/  \__/  \__/  \__ Even row
 \__/  \__/  \__/  \__/   Odd  row