我正在使用Rx
Swift来获取一些网络数据,而我在执行每次迭代数组的请求时遇到了麻烦.这是我的想法：
>我有一个API端点,它返回一个不包含位置数据的Objs数组.然后我将循环遍历Objs数组,并为每个获取Obj id的位置详细信息.像这样的东西：
(代码简化)
var arrayObj = networkClient.request(getobjsEndpoint)
.fetchObjLocationDetails(withNetworkClient: networkClient)
>而fetchObjLocationDetails()将类似于：
(代码简化)
extension ObservableType where E == [Obj]? {
func fetchObjsLocationDetails(withNetworkClient networkClient: NetworkClient) -> Observable<[Obj]?> {
return flatMap { Objs -> Observable<[Obj]?> in
guard let unwrappedobjs = Objs as [Obj]? else { return Observable.just(nil) }
let disposeBag = disposeBag()
var populatedobjs = [Obj]()
unwrappedobjs.forEach { obj in
let getLocationDetailsEndpoint = WeDriveParkAPI.getLocation(id: String(obj.id))
networkClient.request(getLocationDetailsEndpoint)
.observeOn(MainScheduler.instance)
.subscribe(onNext: { json in
guard let populatedobj = Obj.fromJSON(json) as Obj? else { return }
populatedobjs += [populatedobj]
},onError:{ e in
}).adddisposableto(disposeBag)
}
return Observable.just(populatedobjs)
}
}
}
这个解决方案并没有真正起作用,因为代码甚至没有进入订阅下一个闭包.
请记住,我是Swift和RxSwift编程的新手,所以要温柔:)任何帮助将不胜感激.
而不是制作自定义运算符,您可以使用内置.
networkClient.request(getobjsEndpoint)
.map({ (objs:[Obj]?) -> [Obj] in
if let objs = objs {
return objs
} else {
throw NSError(domain: "Objs is nil",code: 1,userInfo: nil)
}
})
.flatMap({ (objs:[Obj]) -> Observable<[Obj]> in
return objs.toObservable().flatMap({ (obj:Obj) -> Observable<Obj> in
let getLocationDetailsEndpoint = WeDriveParkAPI.getLocation(id: String(obj.id))
return self.networkClient.request(getLocationDetailsEndpoint)
.map({ (obj:Obj?) -> Obj in
if let obj = obj {
return obj
} else {
throw NSError(domain: "Obj is nil",userInfo: nil)
}
})
}).toArray()
})
.subscribeNext({ (objs:[Obj]) in
print("Populated objects:")
print(objs)
}).adddisposableto(bag)