我有一个像这样的长字符串:
je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?
我想在之后拆分字符串:之前? .所以我想进入数组:
{e,es,e,ons,ez,en}
我知道我可以这样做:
NSArray *subStrings = [stringtochange componentsSeparatedByString:@":"];
但这还不够.
我该怎么办?任何帮助将不胜感激!
解决方法
另一种选择可能是使用
NSRegularExpression类.
使用这种模式:
\\:([^\?]+)\?
示例代码:
Nsstring *sample = @"je!tress:e?tu!tress:es?il!tress:e?nous!tress:ons?vous!tress:ez?ils!tress:ent?"; Nsstring *pattern = @"\\:([^\?]+)\?"; NSError *error = NULL; NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:NSRegularExpressionCaseInsensitive error:&error]; NSArray *matches = [regex matchesInString:sample options:0 range:NSMakeRange(0,[sample length])]; if(!error && [matches count] > 0) { for (NSTextCheckingResult *match in matches) { NSRange matchRange = [match range]; NSLog(@"%@",[sample substringWithRange:matchRange]); } }
输出:
2015-07-03 12:16:39.037 TestRegex[3479:48301] :e 2015-07-03 12:16:39.039 TestRegex[3479:48301] :es 2015-07-03 12:16:39.039 TestRegex[3479:48301] :e 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ons 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ez 2015-07-03 12:16:39.040 TestRegex[3479:48301] :ent