我有一个文本字段,我希望文本输入包含超过3个字母,以进行验证.如果文本通过验证,则应启用下面的按钮.当按钮收到触地事件时,我想使用视图模型的属性触发操作.
由于目前关于RAC 3.0测试版的资源非常少,我通过阅读框架的Github repo上的QA来实现以下内容.这是我到目前为止所能提出的:
viewmodel.swift
class viewmodel {
var text = MutableProperty<String>("")
let action: Action<String,Bool,NoError>
let validatedTextProducer: SignalProducer<AnyObject?,NoError>
init() {
let validation: Signal<String,NoError> -> Signal<AnyObject?,NoError> = map ({
string in
return (count(string) > 3) as AnyObject?
})
validatedTextProducer = text.producer.lift(validation)
//Dummy action for Now. Will make a network request using the text property in the real app.
action = Action { _ in
return SignalProducer { sink,disposable in
sendNext(sink,true)
sendCompleted(sink)
}
}
}
}
ViewController.swift
class ViewController: UIViewController {
private lazy var txtField: UITextField = {
return createTextFieldAsSubviewOfView(self.view)
}()
private lazy var button: UIButton = {
return createButtonAsSubviewOfView(self.view)
}()
private lazy var buttonEnabled: DynamicProperty = {
return DynamicProperty(object: self.button,keyPath: "enabled")
}()
private let viewmodel = viewmodel()
private var cocoaAction: CocoaAction?
override func viewDidLoad() {
super.viewDidLoad()
view.setNeedsUpdateConstraints()
bindSignals()
}
func bindSignals() {
viewmodel.text <~ textSignal(txtField)
buttonEnabled <~ viewmodel.validatedTextProducer
cocoaAction = CocoaAction(viewmodel.action,input:"Actually I don't need any input.")
button.addTarget(cocoaAction,action: CocoaAction.selector,forControlEvents: UIControlEvents.TouchDown)
viewmodel.action.values.observe(next: {value in
println("view model action result \(value)")
})
}
override func updateViewConstraints() {
super.updateViewConstraints()
//Some autolayout code here
}
}
RACUtilities.swift
func textSignal(textField: UITextField) -> SignalProducer<String,NoError> {
return textField.rac_textSignal().toSignalProducer()
|> map { $0! as! String }
|> catch {_ in SignalProducer(value: "") }
}
使用此设置,当视图模型的文本超过3个字符时,该按钮将启用.当用户点击按钮时,视图模型的动作运行,我可以将返回值设置为true.到现在为止还挺好.
我的问题是:在视图模型的操作中,我想使用其存储的文本属性并更新代码以使用它来发出网络请求.所以,我不需要视图控制器端的输入.我怎么能不要求我的Action属性输入?
解决方法
An action must indicate the type of input it accepts,the type of output it produces,and what kinds of errors can occur (if any).
因此,目前无法在没有输入的情况下定义Action.
我想你可以通过制作AnyObject来声明你不关心输入吗?并使用方便初始化器创建CocoaAction:
cocoaAction = CocoaAction(viewmodel.action)
补充说明
>我不喜欢使用AnyObject?而不是Bool for validatedTextProducer.我想你更喜欢它,因为绑定到buttonEnabled属性需要AnyObject?.我宁愿把它扔在那里,而不是牺牲我的视图模型的类型清晰度(见下面的例子).
>您可能希望在视图模型级别以及UI上限制Action的执行,例如:
class viewmodel {
var text = MutableProperty<String>("")
let action: Action<AnyObject?,NoError>
// if you want to provide outside access to the property
var textValid: PropertyOf<Bool> {
return PropertyOf(_textValid)
}
private let _textValid = MutableProperty(false)
init() {
let validation: Signal<String,NoError> -> Signal<Bool,NoError> = map { string in
return count(string) > 3
}
_textValid <~ text.producer |> validation
action = Action(enabledIf:_textValid) { _ in
//...
}
}
}
并绑定到buttonEnabled:
func bindSignals() {
buttonEnabled <~ viewmodel.action.enabled.producer |> map { $0 as AnyObject }
//...
}