我试图在
Windows下运行以下python服务器：
"""
An echo server that uses select to handle multiple clients at a time.
Entering any line of input at the terminal will exit the server.
"""
import select
import socket
import sys
host = ''
port = 50000
backlog = 5
size = 1024
server = socket.socket(socket.AF_INET,socket.soCK_STREAM)
server.bind((host,port))
server.listen(backlog)
input = [server,sys.stdin]
running = 1
while running:
inputready,outputready,exceptready = select.select(input,[],[])
for s in inputready:
if s == server:
# handle the server socket
client,address = server.accept()
input.append(client)
elif s == sys.stdin:
# handle standard input
junk = sys.stdin.readline()
running = 0
else:
# handle all other sockets
data = s.recv(size)
if data:
s.send(data)
else:
s.close()
input.remove(s)
server.close()
我收到错误消息(10038,’尝试对非套接字的操作’).这可能与python文档中的the remark有关,“Windows上的文件对象是不可接受的,但套接字是.在Windows上,底层的select()函数由WinSock库提供,并且不处理不具有的文件描述符来自WinSock.“在互联网上有很多关于这个主题的帖子,但它们对我来说太技术或者根本不清楚.所以我的问题是：有没有什么方法可以在Windows下使用python中的select()语句？请添加一些示例或修改上面的代码.谢谢！
看起来它不喜欢sys.stdin
如果您将输入更改为此
input = [server]
例外情况将会消失.
这是从the doc
Note:
File objects on Windows are not acceptable,but sockets are. On Windows,the
underlying select() function is provided by the WinSock library,and does not
handle file descriptors that don’t originate from WinSock.