我有以下,无论我尝试什么命令窗口再次打开和关闭.没有显示图表,也没有写入文件.任何有c使用gnuplot的解决方案的人.我有4.4和4.6rc1可用.
#ifdef WIN32
gp = _popen("C:\Program Files (x86)\gnuplot\bin\pgnuplot.exe","w");
#else
gp = popen("gnuplot -persist","w");
#endif
if (gp == NULL)
return -1;
/* fprintf(gp,"unset border\n");
fprintf(gp,"set clip\n");
fprintf(gp,"set polar\n");
fprintf(gp,"set xtics axis nomirror\n");
fprintf(gp,"set ytics axis nomirror\n");
fprintf(gp,"unset rtics\n");
fprintf(gp,"set samples 160\n");
fprintf(gp,"set zeroaxis");
fprintf(gp," set trange [0:2*pi]");*/
fprintf(gp,"set term png\n");
fprintf(gp,"set output \"c:\\printme.png\"");
fprintf(gp,"plot .5,1,1.5\n");
fprintf(gp,"pause -1\n");
fflush(gp);
以下程序已在Windows上使用Visual Studio和MinGW编译器以及使用gcc的GNU / Linux进行了测试. gnuplot二进制文件必须位于路径上,而在Windows上,必须使用二进制文件的管道pgnuplot版本.
我发现Windows管道比GNU / Linux上的相应管道慢得多.对于大型数据集,在Windows上通过管道将数据传输到gnuplot很慢并且通常不可靠.此外,按键等待代码在GNU / Linux上更有用,其中一旦调用pclose(),绘图窗口将关闭.
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
// Tested on:
// 1. Visual Studio 2012 on Windows
// 2. Mingw gcc 4.7.1 on Windows
// 3. gcc 4.6.3 on GNU/Linux
// Note that gnuplot binary must be on the path
// and on Windows we need to use the piped version of gnuplot
#ifdef WIN32
#define GNUPLOT_NAME "pgnuplot -persist"
#else
#define GNUPLOT_NAME "gnuplot"
#endif
int main()
{
#ifdef WIN32
FILE *pipe = _popen(GNUPLOT_NAME,"w");
#else
FILE *pipe = popen(GNUPLOT_NAME,"w");
#endif
if (pipe != NULL)
{
fprintf(pipe,"set term wx\n"); // set the terminal
fprintf(pipe,"plot '-' with lines\n"); // plot type
for(int i = 0; i < 10; i++) // loop over the data [0,...,9]
fprintf(pipe,"%d\n",i); // data terminated with \n
fprintf(pipe,"%s\n","e"); // termination character
fflush(pipe); // flush the pipe
// wait for key press
std::cin.clear();
std::cin.ignore(std::cin.rdbuf()->in_avail());
std::cin.get();
#ifdef WIN32
_pclose(pipe);
#else
pclose(pipe);
#endif
}
else
std::cout << "Could not open pipe" << std::endl;
return 0;
}