我正在开展我的第一个
Java项目,实施一个名为“HeartRates”的课程,该课程取得用户的出生日期,并返回其最大和目标心率.主要测试程序中的一切工作除了一件事之外,我无法弄清楚在异常被捕获后如何停止打印其余的代码.
我不太确定代码中的异常被捕获的全部部分,因为它是由教授给我们复制和粘贴的.如果任何人可以告诉我如何在发生错误后终止程序,或者打印一个自定义的错误信息,并阻止程序进一步执行,我将不胜感激.
这是代码：
import java.util.Scanner;
import java.util.GregorianCalendar;
import javax.swing.JOptionPane;
public class HeartRatesTest {
public static void main(String[] args) {
HeartRates test= new HeartRates();
Scanner input = new Scanner( system.in );
GregorianCalendar gc = new GregorianCalendar();
gc.setLenient(false);
JOptionPane.showMessageDialog(null,"Welcome to the Heart Rate Calculator");;
test.setFirstName(JOptionPane.showInputDialog("Please enter your first name: \n"));
test.setLastName(JOptionPane.showInputDialog("Please enter your last name: \n"));
JOptionPane.showMessageDialog(null,"Now enter your date of birth in Month/Day/Year order (hit enter after each): \n");
try{
String num1= JOptionPane.showInputDialog("Month: \n");
int m= Integer.parseInt(num1);
test.setMonth(m);
gc.set(GregorianCalendar.MONTH,test.getMonth());
num1= JOptionPane.showInputDialog("Day: \n");
m= Integer.parseInt(num1);
test.setDay(m);
gc.set(GregorianCalendar.DATE,test.getDay());
num1= JOptionPane.showInputDialog("Year: \n");
m= Integer.parseInt(num1);
test.setYear(m);
gc.set(GregorianCalendar.YEAR,test.getYear());
gc.getTime(); // exception thrown here
}
catch (Exception e) {
e.printstacktrace();
}
String message="information for "+test.getFirstName()+" "+test.getLastName()+": \n\n"+"dob: "+ test.getMonth()+"/" +test.getDay()+ "/"
+test.getYear()+ "\nAge: "+ test.getAge()+"\nMax Heart Rate: "+test.getMaxHR()+" BPM\nTarget Heart Rate(range): "+test.getTargetHRLow()
+" - "+test.getTargetHRHigh()+" BPM";
JOptionPane.showMessageDialog(null,message);
}
解决方法
不太确定为什么要在异常被捕获后终止应用程序 – 修正错误是不是更好？
在任何情况下,在你的catch块：
catch(Exception e) {
e.printstacktrace(); //if you want it.
//You Could always just System.out.println("Exception occurred.");
//Though the above is rather unspecific.
System.exit(1);
}