java – XPath normalize-space()返回一系列规范化字符串

我需要使用XPath函数normalized-space()来规范化我想要从X HTML文档中提取的文本： http://test.anahnarciso.com/clean_bigbook_0.html

我正在使用以下表达式：

//*[@slot="address"]/normalize-space(.)

这在我用来测试XPath表达式的Qizx Studio中非常有效.

let $doc := doc('http://test.anahnarciso.com/clean_bigbook_0.html')
    return $doc//*[@slot="address"]/normalize-space(.)

这个简单的查询返回一系列xs：string.

144 Hempstead Tpke
403 West St
880 Old Country Rd
8412 164th St
8412 164th St
1 Irving Pl
1622 McDonald Ave
255 Conklin Ave
22011 Hempstead Ave
7909 Queens Blvd
11820 Queens Blvd
1027 Atlantic Ave
1068 Utica Ave
1002 Clintonville St
1002 Clintonville St
1156 Hempstead Tpke
Route 49
10007 Rockaway Blvd
12694 Willets Point Blvd
343 James St

现在,我想在我的Java代码中使用前一个表达式.

String exp = "//*[@slot=\"address"\"]/normalize-space(.)";
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile(exp);
Object result = expr.evaluate(doc,XPathConstants.NODESET);

但是最后一行抛出异常：

无法将XPath值转换为Java对象：必需的类是org.w3c.dom.NodeList;提供的值具有类型xs：string

很明显,我应该改变XPathConstants.NODESET;我尝试了XPathConstants.STRING,但它只返回序列的第一个元素.

我怎样才能获得类似Strings数组的东西？

提前致谢.

XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr;

String select = "//*[@slot='address']";
expr = xpath.compile(select);
NodeList result = (NodeList)expr.evaluate(input,XPathConstants.NODESET);

String normalize = "normalize-space(.)";
expr = xpath.compile(normalize);

int length = result.getLength();
for (int i = 0; i < length; i++) {
    System.out.println(expr.evaluate(result.item(i),XPathConstants.STRING));
}