嘿家伙我试图找到隐藏字符串的方法,但我发现的代码只适用于我的应用程序…有没有办法用“*”或“ – ”隐藏字符串中的字符,如果有的话是有人可以请解释
解决方法
这是用于输入密码吗？考虑以下：
class Password {
final String password; // the string to mask
Password(String password) { this.password = password; } // needs null protection
// allow this to be equal to any string
// reconsider this approach if adding it to a map or something?
public boolean equals(Object o) {
return password.equals(o);
}
// we don't need anything special that the string doesnt
public int hashCode() { return password.hashCode(); }
// send stars if anyone asks to see the string - consider sending just
// "******" instead of the length,that way you don't reveal the password's length
// which might be protected information
public String toString() {
StringBuilder sb = new StringBuilder();
for(int i = 0; < password.length(); i++)
sb.append("*");
return sb.toString();
}
}
或者对于刽子手的方法
class Hangman {
final String word;
final BitSet revealed;
public Hangman(String word) {
this.word = word;
this.revealed = new BitSet(word.length());
reveal(' ');
reveal('-');
}
public void reveal(char c) {
for(int i = 0; i < word.length; i++) {
if(word.charat(i) == c) revealed.set(i);
}
}
public boolean solve(String guess) {
return word.equals(guess);
}
public String toString() {
StringBuilder sb = new StringBuilder(word.length());
for(int i = 0; i < word.length; i++) {
char c = revealed.isSet(i) ? word.charat(i) : "*";
}
return sb.toString();
}
}