我正在使用Simple
XML来解析来自不同房地产经纪人的属性列表的XML提要. XML Feed的相关部分看起来像这样：
<branch name="Trustee Realtors">
<properties>
<property>
<reference>1</reference>
<price>275000</price>
<bedrooms>3</bedrooms>
</property>
<property>
<reference>2</reference>
<price>350000</price>
<bedrooms>4</bedrooms>
</property>
<property>
<reference>3</reference>
<price>128500</price>
<bedrooms>4</bedrooms>
</property>
</properties>
</branch>
<branch name="Quick-E-Realty Inc">
<properties>
<property>
<reference>4</reference>
<price>180995</price>
<bedrooms>3</bedrooms>
</property>
</properties>
</branch>
然后转换为这样的数组：
$xml = file_get_contents($filename); $xml = simplexml_load_string($xml); $xml_array = json_decode(json_encode((array) $xml),1); $xml_array = array($xml->getName() => $xml_array);
我遇到的问题是,当创建数组时,单个列表的数据在数组中与多个列表的位置不同 – 我不确定如何解释这个,但如果我var_dump()它看起来像这样的多个项目的数组：
array(3) {
[0]=>
array(3) {
["reference"]=>
string(4) "0001"
["price"]=>
string(6) "275000"
["bedrooms"]=>
int(3)
}
[1]=>
array(3) {
["reference"]=>
string(4) "0002"
["price"]=>
string(6) "350000"
["bedrooms"]=>
int(4)
}
[2]=>
array(3) {
["reference"]=>
string(4) "0003"
["price"]=>
string(6) "128500"
["bedrooms"]=>
int(2)
}
}
如果我var_dump()单个列表的数组,它看起来像这样：
array(3) {
["reference"]=>
string(4) "0004"
["price"]=>
string(6) "180995"
["bedrooms"]=>
int(3)
}
但我需要它看起来像这样：
array(1) {
[0]=>
array(3) {
["reference"]=>
string(4) "0004"
["price"]=>
string(6) "180995"
["bedrooms"]=>
int(3)
}
}
这些数组中的每一个都代表来自单个房地产经纪人的房产列表.我不确定这是否只是SimpleXML或json函数的工作方式,但我需要的是使用相同的格式(包含属性列表的数组是[0]键的值).
提前致谢！
SimpleXML像这样古怪.我最近使用它试图使配置文件“更容易”编写,并在过程中发现SimpleXML并不总是一致.在这种情况下,我认为您将受益于简单地检测< property>是一个集合中唯一的一个,如果是,那么将它自己包装在一个数组中,然后将它发送到你的循环中.
注意：[‘root’]是因为我需要包装’< root>< / root>‘ XML周围的元素,使我的测试工作.
//Rebuild the properties listings
$rebuild = array();
foreach($xml_array['root']['branch'] as $key => $branch) {
$branchName = $branch['@attributes']['name'];
//Check to see if 'properties' is only one,if it
//is then wrap it in an array of its own.
if(is_array($branch['properties']['property']) && !isset($branch['properties']['property'][0])) {
//Only one propery found,wrap it in an array
$rebuild[$branchName] = array($branch['properties']['property']);
} else {
//Multiple properties found
$rebuild[$branchName] = $branch['properties']['property'];
}
}
这需要重建您的属性.感觉有点hackish.但基本上你在这里检测到缺少多维数组：
if(is_array($branch['properties']['property']) && !isset($branch['properties']['property'][0]))
如果您没有找到多维数组,那么您明确地生成单个< property>中的一个.然后,为了测试所有内容都已正确重建,您可以使用以下代码：
//Now do your operation...whatever it is.
foreach($rebuild as $branch => $properties) {
print("Listings for $branch:\n");
foreach($properties as $property) {
print("Reference of " . $property['reference'] . " sells at $" . $property['price'] . " for " . $property['bedrooms'] . " bedrooms.\n");
}
print("\n");
}
这会产生以下输出：
Listings for Trustee Realtors: Reference of 1 sells at $275000 for 3 bedrooms. Reference of 2 sells at $350000 for 4 bedrooms. Reference of 3 sells at $128500 for 4 bedrooms. Listings for Quick-E-Realty Inc: Reference of 4 sells at $180995 for 3 bedrooms.
并且重建的转储将产生：
Array
(
[Trustee Realtors] => Array
(
[0] => Array
(
[reference] => 1
[price] => 275000
[bedrooms] => 3
)
[1] => Array
(
[reference] => 2
[price] => 350000
[bedrooms] => 4
)
[2] => Array
(
[reference] => 3
[price] => 128500
[bedrooms] => 4
)
)
[Quick-E-Realty Inc] => Array
(
[0] => Array
(
[reference] => 4
[price] => 180995
[bedrooms] => 3
)
)
)
我希望这可以帮助您更接近问题的解决方案.