我有两节课.一个包含其他类的列表：
public string Name { get; set; }
public string Surname { get; set; }
public int Age { get; set; }
public List<Models.Occupation> Occupations { get; set; }
第二类如下
public string Name { get; set; }
public string Industry { get; set; }
我的控制器呈现视图
Person p = new Person()
{
Name = "megan",Surname = "du Preez",Id = 0,Age = 22
};
return View(p);
在视图中
@model Models.Person
<form id="person">
<div>
@Html.TextBoxFor(mp => mp.Name)
@Html.TextBoxFor(mp => mp.Surname)
@(Html.Kendo().Grid<Models.Occupation>()
.Name("Occupations")
.Columns(columns =>
{
columns.Bound(e => e.Name);
columns.Bound(e => e.Industry);
})
)
.DataSource(dataSource => dataSource
.Ajax()
.Read(read => read.Action("Occupations_Read","People",new { Name = Model.Name}))
)
</div>
@Html.Kendo().Button().Name("btnTest").Content("Create")
这读取人员职业如下
List<Models.Occupation> oc = new List<Models.Occupation>();
oc.Add(new Models.Occupation() { CategoryName = "Lecturer" });
oc.Add(new Models.Occupation() { CategoryName = "Student" });
oc.Add(new Models.Occupation() { CategoryName = "Janitor" });
return Json(oc.ToDataSourceResult(request));
所有这些都呈现了我的观点,一切正常,但在表单帖子上我想将所有内容发送回动作
[HttpPost]
public JsonResult PersonPost(Models.Person p)
{
//do stuff
}
我可以使用以下javascript轻松发布Person的名字和Surname
$("#btnTest").click(function (e) {
e.preventDefault();
$.ajax({
url: "/Tasks/PersonPost",type: 'POST',data: $('#person').serialize(),dataType: 'json',success: function (data) {
}
});
});
但网格中的职业不会被序列化并回发到控制器操作.
我的问题是如何将整个模型与视图中的职业列表发布到控制器.
解决方法
试试这个..
@(Html.Kendo().Grid<Models.Occupation>()
.Name("Occupations")
.Columns(columns =>
{
columns.Bound(e => e.Name).ClientTemplate("#= Name #" +
"<input type='hidden' name='Occupation[#= index(data)#].Name' value='#= Name #' />";
columns.Bound(e => e.Industry).ClientTemplate("#= Industry #" +
"<input type='hidden' name='Occupation[#= index(data)#].Industry' value='#= Industry#' />";
})
)
.DataSource(dataSource => dataSource
.Ajax()
.Read(read => read.Action("Occupations_Read",new { Name = Model.Name}))
)
[HttpPost]
public JsonResult PersonPost(Models.Person p)
{
//do stuff
}
你应该能够在Person中获得价值.
请添加以下功能..
************** **************的Javascript
//Index function for the WorkOrder Create view
function index(dataItem) {
var data = $("#GridName").data("kendoGrid").dataSource.data();
return data.indexOf(dataItem);
}
Shaz