我有一个小问题,试图malloc这个结构.
这是结构的代码：
这是结构的代码：
typedef struct stats {
int strength;
int wisdom;
int agility;
} stats;
typedef struct inventory {
int n_items;
char **wepons;
char **armor;
char **potions;
char **special;
} inventory;
typedef struct rooms {
int n_monsters;
int visited;
struct rooms *nentry;
struct rooms *sentry;
struct rooms *wentry;
struct rooms *eentry;
struct monster *monsters;
} rooms;
typedef struct monster {
int difficulty;
char *name;
char *type;
int hp;
} monster;
typedef struct dungeon {
char *name;
int n_rooms;
rooms *rm;
} dungeon;
typedef struct player {
int maxhealth;
int curhealth;
int mana;
char *class;
char *condition;
stats stats;
rooms c_room;
} player;
typedef struct game_structure {
player p1;
dungeon d;
} game_structure;
这里是我有一个问题的代码：
dungeon d1 = (dungeon) malloc(sizeof(dungeon));
它给我错误“错误：转换为非标量类型请求”
有人能帮我理解为什么会这样吗？
解决方法
您不能将任何东西投射到结构类型.我想你想写的是：
dungeon *d1 = (dungeon *)malloc(sizeof(dungeon));
但是请不要在C程序中转换malloc()的返回值.
dungeon *d1 = malloc(sizeof(dungeon));
将工作很好,不会隐藏#include错误从你.