假设我有一些来源的输出,我无法访问原始的
PHP创建的数组：
Array
(
[products] => Array
(
[name] => Arduino Nano Version 3.0 mit ATMEGA328P
[id] => 10005
)
[listings] => Array
(
[category] =>
[title] => This is the first line
This is the second line
[subtitle] => This is the first subtitle
This is the second subtitle
[price] => 24.95
[quantity] =>
[stock] =>
[shipping_method] => Slow and cheap
[condition] => New
[defects] =>
)
[table_count] => 2
[tables] => Array
(
[0] => products
[1] => listings
)
)
现在我想输入该数据并且有一个算法重新创建它正在打印的原始数组,所以我可以使用它为我自己的应用程序.
目前,我正在考虑一个sub_str()和regex语句来提取数据并将其适当放置.在我进一步之前,是否有一个更简单的方法,通过已经编写的代码或PHP插件,为我这样做已经在那里？
function print_r_reverse($in) {
$lines = explode("\n",trim($in));
if (trim($lines[0]) != 'Array') {
// bottomed out to something that isn't an array
return $in;
} else {
// this is an array,lets parse it
if (preg_match("/(\s{5,})\(/",$lines[1],$match)) {
// this is a tested array/recursive call to this function
// take a set of spaces off the beginning
$spaces = $match[1];
$spaces_length = strlen($spaces);
$lines_total = count($lines);
for ($i = 0; $i < $lines_total; $i++) {
if (substr($lines[$i],$spaces_length) == $spaces) {
$lines[$i] = substr($lines[$i],$spaces_length);
}
}
}
array_shift($lines); // Array
array_shift($lines); // (
array_pop($lines); // )
$in = implode("\n",$lines);
// make sure we only match stuff with 4 preceding spaces (stuff for this array and not a nested one)
preg_match_all("/^\s{4}\[(.+?)\] \=\> /m",$in,$matches,PREG_OFFSET_CAPTURE | PREG_SET_ORDER);
$pos = array();
$prevIoUs_key = '';
$in_length = strlen($in);
// store the following in $pos:
// array with key = key of the parsed array's item
// value = array(start position in $in,$end position in $in)
foreach ($matches as $match) {
$key = $match[1][0];
$start = $match[0][1] + strlen($match[0][0]);
$pos[$key] = array($start,$in_length);
if ($prevIoUs_key != '') $pos[$prevIoUs_key][1] = $match[0][1] - 1;
$prevIoUs_key = $key;
}
$ret = array();
foreach ($pos as $key => $where) {
// recursively see if the parsed out value is an array too
$ret[$key] = print_r_reverse(substr($in,$where[0],$where[1] - $where[0]));
}
return $ret;
}
}
不是我的代码,发现在这里的意见：print_r“马特”是业主