我试图将视图控制器降级到详细视图控制器,但不能.使用核心数据(第一次).
错误在prepareForSegue方法中,并显示为:“无法将类型”UIViewController“(0x1b81cdc)的值转换为”Patternz.PatternDetailViewController“(0x32488).
(lldb)“
错误在prepareForSegue方法中,并显示为:“无法将类型”UIViewController“(0x1b81cdc)的值转换为”Patternz.PatternDetailViewController“(0x32488).
(lldb)“
不妨理解为什么它不起作用的解释.
这是文件.
ViewController.swift
import UIKit
import CoreData
class ViewController: UIViewController,UITableViewDataSource,UITableViewDelegate {
@IBOutlet weak var tableView: UITableView!
var patterns : [Pattern] = []
var selectedPattern : Pattern? = nil
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view,typically from a nib.
self.tableView.dataSource = self
self.tableView.delegate = self
createTestPatterns()
var context = (UIApplication.sharedApplication().delegate as! AppDelegate).managedobjectContext!
var request = NSFetchRequest(entityName: "Pattern")
var results = context.executeFetchRequest(request,error: nil)
if results != nil {
self.patterns = results! as! [Pattern]
}
}
func createTestPatterns() {
var context = (UIApplication.sharedApplication().delegate as! AppDelegate).managedobjectContext!
var pattern = NSEntityDescription.insertNewObjectForEntityForName("Pattern",inManagedobjectContext: context) as! Pattern
pattern.name = "Dress Shirt"
pattern.frontimage = UIImageJPEGRepresentation(UIImage(named: "examplePattern.jpg"),1)
context.save(nil)
}
func tableView(tableView: UITableView,numberOfRowsInSection section: Int) -> Int {
return self.patterns.count
}
func tableView(tableView: UITableView,cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
var cell = UITableViewCell()
var pattern = self.patterns[indexPath.row]
cell.textLabel!.text = pattern.name
cell.imageView!.image = UIImage(data: pattern.frontimage)
return cell
}
func tableView(tableView: UITableView,didSelectRowAtIndexPath indexPath: NSIndexPath) {
self.selectedPattern = self.patterns[indexPath.row]
self.performSegueWithIdentifier("patternDetailSegue",sender: self)
}
override func prepareForSegue(segue: UIStoryboardSegue,sender: AnyObject?) {
if segue.identifier == "patternDetailSegue" {
var detailViewController = segue.destinationViewController as! PatternDetailViewController // Could not cast value of type 'UIViewController' to 'Patternz.PatternDetailViewController'
detailViewController.pattern = self.selectedPattern
}
}
}
PatternDetailViewController.swift
import UIKit
class PatternDetailViewController: UIViewController {
var pattern : Pattern? = nil
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
self.navigationItem.title = self.pattern!.name
}
}
解决方法
正如你所说,这个问题在这些方面:
if segue.identifier == "patternDetailSegue" {
var detailViewController = segue.destinationViewController as! PatternDetailViewController
// Could not cast value of type 'UIViewController' to 'Patternz.PatternDetailViewController'
该错误消息告诉您,该segue的destinationViewController实际上不是一个PatternDetailViewController.你可能会认为是,但不是.你需要在故事板中检查这个段落,看看它的目的地是什么.
错误消息将其描述为UIViewController的事实使我怀疑您在故事板中的此视图控制器的Identity检查器中忘记输入任何视图控制器类型: